8x^2+2y^2-128=0

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Solution for 8x^2+2y^2-128=0 equation:


Simplifying
8x2 + 2y2 + -128 = 0

Reorder the terms:
-128 + 8x2 + 2y2 = 0

Solving
-128 + 8x2 + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '128' to each side of the equation.
-128 + 8x2 + 128 + 2y2 = 0 + 128

Reorder the terms:
-128 + 128 + 8x2 + 2y2 = 0 + 128

Combine like terms: -128 + 128 = 0
0 + 8x2 + 2y2 = 0 + 128
8x2 + 2y2 = 0 + 128

Combine like terms: 0 + 128 = 128
8x2 + 2y2 = 128

Add '-2y2' to each side of the equation.
8x2 + 2y2 + -2y2 = 128 + -2y2

Combine like terms: 2y2 + -2y2 = 0
8x2 + 0 = 128 + -2y2
8x2 = 128 + -2y2

Divide each side by '8'.
x2 = 16 + -0.25y2

Simplifying
x2 = 16 + -0.25y2

Reorder the terms:
-16 + x2 + 0.25y2 = 16 + -0.25y2 + -16 + 0.25y2

Reorder the terms:
-16 + x2 + 0.25y2 = 16 + -16 + -0.25y2 + 0.25y2

Combine like terms: 16 + -16 = 0
-16 + x2 + 0.25y2 = 0 + -0.25y2 + 0.25y2
-16 + x2 + 0.25y2 = -0.25y2 + 0.25y2

Combine like terms: -0.25y2 + 0.25y2 = 0.00
-16 + x2 + 0.25y2 = 0.00

The solution to this equation could not be determined.

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